http://www.bbc.co.uk/news/science-environment-20300100
The Bs meson decays to two muons (or mu-mesons). What is the big deal here? In the Reciprocal System, we can identify the Bs meson as (probably) a c-H2 (cosmic deuterium) with four material gravitational charges. It can then decay to two muons, which are really c-Ar with two material gravitational charges. The mass/energy remaining is equivalent to a c-Be with one gravitational charge. The Reciprocal System mass is equal to 1862.95/(n+.5 x G) +I x 931.478 MeV/c^2, where n = cosmic atomic number, G = cosmic gravitational charges, I = material gravitational charges. Present-day theories say that very heavy particles should be found in decay products, but this recent CERN experiment shows that that is unlikely. From the standpoint of the Reciprocal System, it’s rather difficult to imagine a cosmic particle heavier than what’s been calculated for Bs here, 5366.3 MeV/c^2. Of course, energy may be converted to any material atom, such as Cs, which would, obviously, be much heavier–but it’s not a cosmic (or anti-) particle.